Logo Questions Linux Laravel Mysql Ubuntu Git Menu
 

jQuery/AJAX call with a timer

How can i implement the below code with jQuery/AJAX timer,(I have created 2 URL classes by using web.py.Here 1st URL will return a random number between 1 and 250.I have created an AJAX call in the 2nd URL,so that when you hit the button ,AJAX will call the values from the 1st URL and it will display inside the text box),Now i just want to modify the code like during every 5 seconds AJAX should call the numbers from 1st URL and it should display inside the text box.Is there any way to solve this problem by using jQuery/AJAX timer.

import web
import random

urls = (
  '/', 'main',
  '/random','fill')


app = web.application(urls, globals(), True)

class main:
    def GET(self):
       return  random.randint(1,250)


class fill:
    def GET(self):
        return'''
        <html>
        <head>
        <script type="text/javascript" src="http://ajax.microsoft.com/ajax/jquery/jquery-1.4.2.min.js"></script>
        <script type="text/javascript">
        $(document).ready(function(){
        $("button").click(function(){
          $.ajax({url:"http://127.0.0.1:8080/", success:function(result){
             $("#text").val(result);
          }});
        });});
        </script>
        </head>
        <body>


        <form>
        <input type = "text" id = "text"/>
        </form>
        <h2>Hit the button to view random numbers</h2>
        <button>Click</button>
        </body>
        </html>'''



if __name__ == "__main__":
    app.run()
like image 538
Sreehari K M Avatar asked Jul 27 '11 06:07

Sreehari K M


1 Answers

When the ajax call returns from the server, create a timer that will poll the server again n milliseconds later. This approach should work regardless of how long it takes for the ajax call to complete.

$("button").click(function refreshText(){
    $.ajax({
        url:"http://127.0.0.1:8080/",
        success:function(result){
            $("#text").val(result);
            setTimeout(refreshText, 5000);
        }
    });
});
like image 176
Chris Shouts Avatar answered Oct 16 '22 00:10

Chris Shouts