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Jquery - Uncaught TypeError: Cannot use 'in' operator to search for '324' in

I'm trying to send a Get request by ajax and output json data that is returned by server in html.

But, I got this error.

Uncaught TypeError: Cannot use 'in' operator to search for '324' in 
[{"id":50,"name":"SEO"},{"id":22,"name":"LPO",}]

This is my code that sends a Get request to php file by ajax. When I use $.each method, it get the error that I showed in the above.

parentCat.on('change', function(e){
    parentCatId = $(this).val();

    $.get(
        'index.php?r=admin/post/ajax',
        {"parentCatId":parentCatId},
        function(data){                     
            $.each(data, function(key, value){
                console.log(key + ":" + value)
            })
        }
    )

})

This is my PHP code that returns query result in json format.

public function actionAjax(){

    $parentCatId=$_GET['parentCatId'];

        $catData = Category::getTargetCategoryData($parentCatId);

        echo CJSON::encode($catData);
        Yii::app()->end();

}

json data outputted by this php is like this.

[{"id":50,"name":"SEO"},{"id":22,"name":"LPO",}]

Anyone knows how to fix this problem?

Please help me out. Thanks in advance :)

like image 462
Hayato Avatar asked Aug 29 '13 04:08

Hayato


2 Answers

You have a JSON string, not an object. Tell jQuery that you expect a JSON response and it will parse it for you. Either use $.getJSON instead of $.get, or pass the dataType argument to $.get:

$.get(
    'index.php?r=admin/post/ajax',
    {"parentCatId":parentCatId},
    function(data){                     
        $.each(data, function(key, value){
            console.log(key + ":" + value)
        })
    },
    'json'
);
like image 86
Paul Avatar answered Nov 08 '22 15:11

Paul


You can also use $.parseJSON(data) that will explicit convert a string thats come from a PHP script to a real JSON array.

like image 22
HansH Avatar answered Nov 08 '22 14:11

HansH