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Nothing easier than that man. Try this one:
<?xml version="1.0" encoding="iso-8859-1"?>
<html>
<head>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.3.2/jquery.min.js"></script>
<link rel="stylesheet" href="http://ajax.googleapis.com/ajax/libs/jqueryui/1.7.1/themes/base/jquery-ui.css" type="text/css" />
<script src="http://ajax.googleapis.com/ajax/libs/jqueryui/1.7.1/jquery-ui.min.js"></script>
<style>
.loading { background: url(/img/spinner.gif) center no-repeat !important}
</style>
</head>
<body>
<a class="ajax" href="http://www.google.com">
Open as dialog
</a>
<script type="text/javascript">
$(function (){
$('a.ajax').click(function() {
var url = this.href;
// show a spinner or something via css
var dialog = $('<div style="display:none" class="loading"></div>').appendTo('body');
// open the dialog
dialog.dialog({
// add a close listener to prevent adding multiple divs to the document
close: function(event, ui) {
// remove div with all data and events
dialog.remove();
},
modal: true
});
// load remote content
dialog.load(
url,
{}, // omit this param object to issue a GET request instead a POST request, otherwise you may provide post parameters within the object
function (responseText, textStatus, XMLHttpRequest) {
// remove the loading class
dialog.removeClass('loading');
}
);
//prevent the browser to follow the link
return false;
});
});
</script>
</body>
</html>
Note that you can't load remote from local, so you'll have to upload this to a server or whatever. Also note that you can't load from foreign domains, so you should replace href of the link to a document hosted on the same domain (and here's the workaround).
Cheers
To avoid adding extra divs when clicking on the link multiple times, and avoid problems when using the script to display forms, you could try a variation of @jek's code.
$('a.ajax').live('click', function() {
var url = this.href;
var dialog = $("#dialog");
if ($("#dialog").length == 0) {
dialog = $('<div id="dialog" style="display:hidden"></div>').appendTo('body');
}
// load remote content
dialog.load(
url,
{},
function(responseText, textStatus, XMLHttpRequest) {
dialog.dialog();
}
);
//prevent the browser to follow the link
return false;
});`
//Properly Formatted
<script type="text/Javascript">
$(function ()
{
$('<div>').dialog({
modal: true,
open: function ()
{
$(this).load('mypage.html');
},
height: 400,
width: 600,
title: 'Ajax Page'
});
});
Just an addition to nicktea's answer. This code loads the content of a remote page (without redirecting there), and also cleans up when closing it.
<script type="text/javascript">
function showDialog() {
$('<div>').dialog({
modal: true,
open: function () {
$(this).load('AccessRightsConfig.htm');
},
close: function(event, ui) {
$(this).remove();
},
height: 400,
width: 600,
title: 'Ajax Page'
});
return false;
}
</script>
Neither of the first two answers worked for me with multiple elements that can open dialogs that point to different pages.
This feels like the cleanest solution, only creates the dialog object once on load and then uses the events to open/close/display appropriately:
$(function () {
var ajaxDialog = $('<div id="ajax-dialog" style="display:hidden"></div>').appendTo('body');
ajaxDialog.dialog({autoOpen: false});
$('a.ajax-dialog-opener').live('click', function() {
// load remote content
ajaxDialog.load(this.href);
ajaxDialog.dialog("open");
//prevent the browser from following the link
return false;
});
});
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