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jquery ui dialog open multiple dialog boxes using the same class on the button and the content div

i want to open multiple dialog boxes by using the same class on both the button and the content div. The below works but only for the first time.

jQuery('.helpDialog').hide();

jQuery('.helpButton').click(function() {  
    jQuery(this).next('.helpDialog').dialog({  
    autoOpen: true,  
    title: 'Help',  
    width: 500,  
    height: 300,  
    position: [180,10],  
    draggable: true,    
    resizable: false,  
    modal: false  
    });  
return false;  
});  

we know the reason for this http://blog.nemikor.com/2009/04/08/basic-usage-of-the-jquery-ui-dialog/ "the second call is ignored because the dialog has already been instantiated on that element."

But when i fix that problem by trying the code below, the dialog box no longer opens. Can anyone help? Thanks in advance

jQuery('.helpDialog').hide();

jQuery(function() {  
    jQuery('.helpDialog').dialog({  
        autoOpen: false,  
        modal: true,  
        title: 'Info',  
        width: 600,  
        height: 400,  
        position: [200,0],  
        draggable: false  
    });  
});  

jQuery('.helpButton').click(function() {  
    jQuery(this).next('.helpDialog').dialog('open');  
    return false;  
});  
like image 301
MichaelAntoni Avatar asked Dec 23 '10 12:12

MichaelAntoni


2 Answers

You actually need a different approach here, a non-intuitive one, like this:

jQuery(function($) {
  $('.helpButton').each(function() {  
    $.data(this, 'dialog', 
      $(this).next('.helpDialog').dialog({
        autoOpen: false,  
        modal: true,  
        title: 'Info',  
        width: 600,  
        height: 400,  
        position: [200,0],  
        draggable: false  
      })
    );  
  }).click(function() {  
      $.data(this, 'dialog').dialog('open');  
      return false;  
  });  
});  

You can test it out here.

Why must you do this? because .dialog() moves the content it wraps in dialog elements to the end of the <body>, so .next() will no longer find it...by using jQuery.data() we're maintaining a reference to the dialog we want to open.

like image 66
Nick Craver Avatar answered Sep 21 '22 01:09

Nick Craver


Maybe this code will help you.

<html xmlns="http://www.w3.org/1999/xhtml">
<head runat="server">
    <title></title>
    <link rel="stylesheet" href="Styles/ui-lightness/jquery-ui-1.7.2.custom.css" />

<script src="Scripts/jquery-1.4.1.min.js" type="text/javascript"></script>
    <script src="http://ajax.googleapis.com/ajax/libs/jqueryui/1.8/jquery-ui.min.js" type="text/javascript"></script>
<script type="text/javascript">
    $(document).ready(function () {

        $("#opener1").click(function () {
            $("<div id='dialog1' />").dialog(
            {
                title: 'Basic modal dialog1',
                autoOpen: false,
                width: 600,
                height: 400,
                open: function (event, ui) {
                }
            });

            $("#dialog1").dialog('open').show();
            return false;
        });


        $("#opener2").click(function () {
            $("<div id='dialog2' />").dialog(
            {
                title: 'Basic modal dialog2',
                autoOpen: false,
                width: 600,
                height: 400,
                open: function (event, ui) {
                }
            });

            $("#dialog2").dialog('open').show();
            return false;
        });

    });
</script>

</head>
<body>
    <form id="form1" runat="server">
    <button id="opener1">open the dialog1</button>
    <button id="opener2">open the dialog2</button>

    </form>
</body>
</html>
like image 2
Thomas Avatar answered Sep 22 '22 01:09

Thomas