jquery to slide down - up the form- hidden by default for the first time,

Question

<div><input type="button" id="changePwd" value="Change your password"/></div>
<br/>
<div id="form_pwd">          
    <form method="POST" action="google.com" id="pwdChange">
        <table>
            <tr>
                <td width="175px"><label for="oldPwd">Enter your password</label></td>                
                <td><input type="password" name="newPwd" id="newPwd" size="35"/></td>
            </tr>
            <tr>
                <td><label for="oldPwd_>"Re-enter your password</label></td>
                <td><input type="password" name="newPwd_" id="newPwd_" size="35"/></td>
            </tr>
    <tr>
        <td></td><td><input type="submit" value="Save Password" /></td>
    </tr>
        </table><br/>

    </form>
</div>

<script>
$("#changePwd" ).click(function () 
{
    if ($("#form_pwd").is(":show")) 
    {
    $("#form_pwd").slideDown("normal");
    }
    else
    {
    $("#form_pwd").hide();
    }
});

</script>

i would like to not display the form until the user click the button but I fail to make it work, it displays by default when the page shows up. thank you

Answer 1

add display:none to your div

<div id="form_pwd" style="display:none;">

Answer 2

Try this one.

<script type="text/javascript">
$("#form_pwd" ).hide();
$('#changePwd').click(function() {
  $('#form_pwd').slideToggle('slow', function() {
  });
});
</script>

$("#form_pwd" ).hide(); will hide your form on page load and only show once you click on change your password button.