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I have a table that looks like:
<table> <tr> <td>one</td><td>two</td><td>three</td><td>last</td> </tr> <tr> <td>blue</td><td>red</td><td>green</td><td>last</td> </tr> <tr> <td>Monday</td><td>Tuesday</td><td>Wednesday</td><td>last</td> </tr> </table> What I want is a jquery selector that will choose all but the last td of each table row. I tried:
$("tr td:not(:last)").css("background-color","red"); //changing color just as a test... But instead of all cells but the last on each row being changed, all cells but the very last one in the table are selected. Similarly, if I change it to:
$("tr td:last").css("background-color","red"); the only one that changes is the very last cell. How do I choose the last (or not last) of each row?
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The element Selector. The jQuery element selector selects elements based on the element name. You can select all <p> elements on a page like this: $ ( "p" )
All selectors in jQuery start with the dollar sign and parentheses: $ (). The jQuery element selector selects elements based on the element name. You can select all <p> elements on a page like this:
In order to get the best performance using :selected, first select elements with a standard jQuery selector, then use.filter (":selected"), or precede the pseudo-selector with a tag name or some other selector.
The.class Selector The jQuery.class selector finds elements with a specific class. To find elements with a specific class, write a period character, followed by the name of the class: $ (".test")
Use this:
$('tr td:not(:last-child)').css('background-color', 'red'); It's saying each <td> that's not the last in that particular <tr>
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