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JQuery: if div is visible [duplicate]

I'm using JS as a way of changing the content of an SPA I'm creating. When I press a button to change the content the HTML changes from this:

<div id="selectDiv" style="display: none;">

to this:

<div id="selectDiv" style>

Now part of my SPA has a div that contains a number of checkboxes, each representing a div, and so when I press the submit button, the next div that should be displayed will be the first item in the checkbox list that was selected.

I'm wondering if there's a way in JQuery for the code to "almost detect" which div is now visible. something like this:

if($('#selectDiv').isVisible()){
    //JS code associated with this div.
}

Any suggestions?

like image 685
Mark Avatar asked Nov 07 '16 15:11

Mark


1 Answers

You can use .is(':visible')

Selects all elements that are visible.

For example:

if($('#selectDiv').is(':visible')){

Also, you can get the div which is visible by:

$('div:visible').callYourFunction();

Live example:

console.log($('#selectDiv').is(':visible'));
console.log($('#visibleDiv').is(':visible'));
#selectDiv {
  display: none;  
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="selectDiv"></div>
<div id="visibleDiv"></div>
like image 120
Mosh Feu Avatar answered Oct 20 '22 23:10

Mosh Feu