The discussion begins jQuery: What to do with the list that sortable('serialize') returns?
How to reverse it from last to first, updateList.php?id[]=5&id[]=4&id[]=3&id[]=2&id[]=1&&action=update?
<ul>
<li id="oreder-5">5</li>
<li id="oreder-4">4</li>
<li id="oreder-3">3</li>
<li id="oreder-2">2</li>
<li id="oreder-1">1</li>
<ul>
My code:
$(document).ready(function(){
    order=[];
    $('#list ul').children('li').each(function(idx, elm) { order.push(elm.id.split('-')[1]) });
    $.post('updateList.php', {'order[]': order, action: 'update'});
    function slideout(){
        setTimeout(function(){ $("#response").slideUp("slow", function () {}); }, 2000);
    }
    $("#response").hide();
 $(function() {
    $("#list ul").sortable({ opacity: 0.8, cursor: 'move', update: function() {
   var order = $(this).sortable("serialize") + '&action=update'; 
   $.post("updateList.php", order, function(theResponse){
    $("#response").html(theResponse);
    $("#response").slideDown('slow');
    slideout();
   });
    }});             
 });
});
                This will do it:
var reversed = $(this).sortable("serialize").split("&").reverse().join("&");
var order = reversed + '&action=update'; 
In other words:
Needed order.reverse(); before $.post(..);
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