The discussion begins jQuery: What to do with the list that sortable('serialize') returns?
How to reverse it from last to first, updateList.php?id[]=5&id[]=4&id[]=3&id[]=2&id[]=1&&action=update?
<ul>
<li id="oreder-5">5</li>
<li id="oreder-4">4</li>
<li id="oreder-3">3</li>
<li id="oreder-2">2</li>
<li id="oreder-1">1</li>
<ul>
My code:
$(document).ready(function(){
order=[];
$('#list ul').children('li').each(function(idx, elm) { order.push(elm.id.split('-')[1]) });
$.post('updateList.php', {'order[]': order, action: 'update'});
function slideout(){
setTimeout(function(){ $("#response").slideUp("slow", function () {}); }, 2000);
}
$("#response").hide();
$(function() {
$("#list ul").sortable({ opacity: 0.8, cursor: 'move', update: function() {
var order = $(this).sortable("serialize") + '&action=update';
$.post("updateList.php", order, function(theResponse){
$("#response").html(theResponse);
$("#response").slideDown('slow');
slideout();
});
}});
});
});
This will do it:
var reversed = $(this).sortable("serialize").split("&").reverse().join("&");
var order = reversed + '&action=update';
In other words:
Needed order.reverse(); before $.post(..);
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