jQuery HOW TO?? pass additional parameters to success callback for $.ajax call?

Question

I am trying, in vain it seems, to be able to pass additional parameters back to the success callback method that I have created for a successful ajax call. A little background. I have a page with a number of dynamically created textbox / selectbox pairs. Each pair having a dynamically assigned unique name such as name="unique-pair-1_txt-url" and name="unique-pair-1_selectBox" then the second pair has the same but the prefix is different.

In an effort to reuse code, I have crafted the callback to take the data and a reference to the selectbox. However when the callback is fired the reference to the selectbox comes back as 'undefined'. I read here that it should be doable. I have even tried taking advantage of the 'context' option but still nothing. Here is the script block that I am trying to use:

<script type="text/javascript" language="javascript">
$j = jQuery.noConflict();
function getImages(urlValue, selectBox) {
    $j.ajax({
        type: "GET",
        url: $j(urlValue).val(),
        dataType: "jsonp",
        context: selectBox,
        success:function(data){
         loadImagesInSelect(data)
        } ,
        error:function (xhr, ajaxOptions, thrownError) {
            alert(xhr.status);
            alert(thrownError);
        }

    });
}

function loadImagesInSelect(data) {
var select = $j(this);
select.empty();
$j(data).each(function() {
    var theValue = $j(this)[0]["@value"];
    var theId = $j(this)[0]["@name"];
    select.append("<option value='" + theId + "'>" + theValue + "</option>");
});
select.children(":first").attr("selected", true);

}    
</script>

From what I have read, I feel I am close but I just cant put my finger on the missing link. Please help in your typical ninja stealthy ways. TIA

****UPDATE**** Nick is a true Ninja. They should invent a new badge for that! His answer below does the trick. As he mentions it's 1.4 specific but I can live with that. Here is my final code that is working for any Ninjas in training (and my future reference):

<script type="text/javascript" language="javascript">
$j = jQuery.noConflict();
function getImages(urlValue, selectBox) {
    $j.ajax({
        type: "GET",
        url: urlValue+ '?callback=?',
        dataType: "jsonp",
        context: selectBox,
        success: jQuery.proxy(function (data) {
            var select = $j(this);
            select.empty();
            $j(data).each(function() {
                var theValue = $j(this)[0]["@value"];
                var theId = $j(this)[0]["@name"];
                select.append("<option value='" + theId + "'>" + theValue + "</option>");
            });
            select.children(":first").attr("selected", true);
        }, selectBox),
        error:function (xhr, ajaxOptions, thrownError) {
            alert(xhr.status);
            alert(thrownError);
        }
    });
}
</script>

Answer 1

Put this into your $.ajax parameters.

invokedata: {
    data1: "yourdata",
    data2: "moredata"
}

In the success function use it like this

this.invokedata.data1;
this.invokedata.data2;

Your $.ajax call and the success function must also be a part of the same object. Put your functions in an object and define them like this

function myObject {
    var getImage = function(..) { }
    var loadImagesInSelect = function(..) { }
}

Answer 2

This is what I did, and it also worked fine:

$.ajax('URL', {
    myCustomControl: selectBox,
    myCustomVariable: 'teste',
    data:
    {
       myData: 1
    },
    success: function (data, textStats, jqXHR) {
        myFunction(data, textStats, jqXHR, this.myCustomControl, this.myCustomVariable);
    }   
});

You can add controls and variables to the parameters of your ajax call.