This should be an easy one. I have a variable that I've already declared called $listItems. The declaration looks like this:
var $listItems = $ul.children('li'); // $ul is just a selected unordered list
Later in my code, I'd like to only get the ones that are currently visible. How would I go about that? Something like:
$listItems.parent().children(':visible')?
Thanks.
Answer: Use the jQuery :visible and :hidden Selector You can simply use the jQuery :visible or :hidden selector to select all the visible or hidden elements in an HTML page.
Answer: Use the jQuery :visible Selector You can use the jQuery :visible selector to check whether an element is visible in the layout or not.
The jQuery #id selector uses the id attribute of an HTML tag to find the specific element. An id should be unique within a page, so you should use the #id selector when you want to find a single, unique element.
To check if an element is hidden or not, jQuery :hidden selector can be used. .toggle() function is used to toggle the visibility of an element. Click!
You can use .filter()
to narrow down a set of elements to only those that match a selector (or a function), like this:
$listItems.filter(':visible')
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