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To have a working datepicker on a field, I have to put this script inside my element
$( function() { $( "#date_datepicker" ).datepicker( { dateFormat: "yy-mm-dd" } ); }); Removing the $( function() { makes the datepicker not work.
So does it mean that the $( function() { is the same as $(document).ready?
I'm trying to optimize my javascript codes so knowing this might help.
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So technically they are both the same. Not major difference between these two declaration. They used based on weather you use JavaScript then you should use $(document). ready declaration in other case you use jQuery library which is a part of JavaScript then you should use $(function) declaration.
load(function(){ // ...}) @undefined, this is almost the same as $(document). ready(function(){ ... }) . load() will wait until the graphics are also loaded.
ready() and $(window). load() event is that the code included inside onload function will run once the entire page(images, iframes, stylesheets,etc) are loaded whereas the $(document). ready() event fires before all images,iframes etc. are loaded, but after the whole DOM itself is ready.
ready' function in a page? Can we add more than one 'document. ready' function in a page? Yes we can do it as like I did in below example both the $(document).
See the extract below from http://api.jquery.com/ready/
All three of the following syntaxes are equivalent:
$(document).ready(handler)$().ready(handler)(this is not recommended)$(handler)
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