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JQuery Fancybox not working

I've followed the directions, but Fancybox isn't working right. I think I need some extra eyes to tell me what I am doing wrong.

Any Ideas?

HTML

The code:

<h1><a id="v" class= "letter fancybox" data-fancybox-group="group" href="http://placekitten.com/500/500">V</a></h1>

The References:

CSS (top of page):

<link rel="stylesheet" href="home/css/jquery.fancybox.css?v=2.1.5" type="text/css" media="screen" />

JS (bottom of page, including other js):

<script src="http://code.jquery.com/jquery-latest.min.js" type="text/javascript"></script>
<script src="http://code.jquery.com/ui/1.10.3/jquery-ui.min.js"></script>

<!-- FancyBox -->
<script type="text/javascript" src="home/js/jquery.fancybox.pack.js?v=2.1.5"></script>

JS

main.js (inside of document ready):

$(".fancybox").fancybox({
    openEffect  : 'fade',
    closeEffect : 'fade'
});

I think I should also mention that I didn't put the entire project into one folder. I put the .css and .js files in separate CSS and JS directories and only included the two referenced files. I'm wondering if that has anything to do with it and if I should just copy over the source folder and keep everything in there.

like image 642
Keven Avatar asked Nov 28 '22 11:11

Keven


1 Answers

You should add type field in your Fancybox' config. Fancybox tries to detect type of content, but when you href to e.g. php script which generates image, Fancybox sometimes can't recognize type of content.

Change:

$(".fancybox").fancybox({
   openEffect  : 'fade',
   closeEffect : 'fade'
});

to:

$(".fancybox").fancybox({
   openEffect  : "fade",
   closeEffect : "fade",
   type : "image"
});
like image 188
kampro Avatar answered Dec 09 '22 17:12

kampro