jQuery Clone table row

Question

I have a table with an Add button on the end. When you click this button I want a new table row to be created underneath the current one. I also want the input fields on this row to be blank. I am trying to do this using .clone() but it clones all the rows on the page. Please help. Thanks

Script

$("input.tr_clone_add")         .live('click', function(){               $(this).closest('.tr_clone')                     .clone()                     .insertAfter(".tr_clone")          }); 

HTML

<table width="100%" border="0" cellspacing="0" cellpadding="0" id="table-data"> <tr> <td>Name</td> <td>Location</td> <td>From</td> <td>To</td> <td>Add</td> </tr> <tr class="tr_clone"> <td><input type="text" autofocus placeholder="who" name="who" ></td> <td><input type="text" autofocus placeholder="location" name="location" ></td> <td><input type="text" placeholder="Start Date" name="datepicker_start" class="datepicker"></td> <td><input type="text" placeholder="End Date" name="datepicker_end" class="datepicker"></td> <td><input type="button" name="add" value="Add" class="tr_clone_add"></td> </tr> </table><!-- /table#table-data --> 

Answer 1

Your problem is that your insertAfter:

.insertAfter(".tr_clone") 

inserts after every .tr_clone:

the matched set of elements will be inserted after the element(s) specified by this parameter.

You probably just want to use after on the row you're duplicating. And a little .find(':text').val('') will clear the cloned text inputs; something like this:

var $tr    = $(this).closest('.tr_clone'); var $clone = $tr.clone(); $clone.find(':text').val(''); $tr.after($clone); 

Demo: http://jsfiddle.net/ambiguous/LAECx/ or for a modern jQuery: http://jsfiddle.net/ambiguous/LAECx/3274/

I'm not sure which input should end up with the focus so I've left that alone.