jQuery: click function exclude children.

Question

To do this, stop the click on the child using .stopPropagation:

$(".example").click(function(){
  $(this).fadeOut("fast");
}).children().click(function(e) {
  return false;
});

This will stop the child clicks from bubbling up past their level so the parent won't receive the click.

.not() is used a bit differently, it filters elements out of your selector, for example:

<div class="bob" id="myID"></div>
<div class="bob"></div>

$(".bob").not("#myID"); //removes the element with myID

For clicking, your problem is that the click on a child bubbles up to the parent, not that you've inadvertently attached a click handler to the child.

I'm using following markup and had encoutered the same problem:

<ul class="nav">
    <li><a href="abc.html">abc</a></li>
    <li><a href="def.html">def</a></li>
</ul>

Here I have used the following logic:

$(".nav > li").click(function(e){
    if(e.target != this) return; // only continue if the target itself has been clicked
    // this section only processes if the .nav > li itself is clicked.
    alert("you clicked .nav > li, but not it's children");
});

In terms of the exact question, I can see that working as follows:

$(".example").click(function(e){
   if(e.target != this) return; // only continue if the target itself has been clicked
   $(".example").fadeOut("fast");
});

or of course the other way around:

$(".example").click(function(e){
   if(e.target == this){ // only if the target itself has been clicked
       $(".example").fadeOut("fast");
   }
});

Hope that helps.

Or you can do also:

$('.example').on('click', function(e) { 
   if( e.target != this ) 
       return false;

   // ... //
});

My solution:

jQuery('.foo').on('click',function(event){
    if ( !jQuery(event.target).is('.foo *') ) {
        // code goes here
    } 
});