Join two sql queries

Question

Some DBMSs support the FROM (SELECT ...) AS alias_name syntax.

Think of your two original queries as temporary tables. You can query them like so:

SELECT t1.Activity, t1."Total Amount 2009", t2."Total Amount 2008"
FROM (query1) as t1, (query2) as t2
WHERE t1.Activity = t2.Activity

SELECT Activity, arat.Amount "Total Amount 2008", abull.Amount AS "Total Amount 2009"
FROM
  Activities a
LEFT OUTER JOIN
  (
  SELECT ActivityId, SUM(Amount) AS Amount
  FROM Incomes ibull
  GROUP BY
    ibull.ActivityId
  ) abull
ON abull.ActivityId = a.ActivityID
LEFT OUTER JOIN
  (
  SELECT ActivityId, SUM(Amount) AS Amount
  FROM Incomes2008 irat
  GROUP BY
    irat.ActivityId
  ) arat
ON arat.ActivityId = a.ActivityID
WHERE a.UnitName = ?
ORDER BY Activity

I would just use a Union

In your second query add the extra column name and add a '' in all the corresponding locations in the other queries

Example

//reverse order to get the column names
select top 10 personId, '' from Telephone//No Column name assigned 
Union 
select top 10 personId, loanId from loan

Here's what worked for me:

select visits, activations, simulations, simulations/activations
   as sims_per_visit, activations/visits*100
   as adoption_rate, simulations/activations*100
   as completion_rate, duration/60
   as minutes, m1 as month, Wk1 as week, Yr1 as year 

from
(
    (select count(*) as visits, year(stamp) as Yr1, week(stamp) as Wk1, month(stamp)
    as m1 from sessions group by week(stamp), year(stamp)) as t3

    join

    (select count(*) as activations, year(stamp) as Yr2, week(stamp) as Wk2,
    month(stamp) as m2 from sessions where activated='1' group by week(stamp),
    year(stamp)) as t4

    join

    (select count(*) as simulations, year(stamp) as Yr3 , week(stamp) as Wk3,
    month(stamp) as m3 from sessions where simulations>'0' group by week(stamp),
    year(stamp)) as t5

    join

    (select avg(duration) as duration, year(stamp) as Yr4 , week(stamp) as Wk4,
    month(stamp) as m4 from sessions where activated='1' group by week(stamp),
    year(stamp)) as t6
)
where Yr1=Yr2 and Wk1=Wk2 and Wk1=Wk3 and Yr1=Yr3 and Yr1=Yr4 and Wk1=Wk4

I used joins, not unions (I needed different columns for each query, a join puts it all in the same column) and I dropped the quotation marks (compared to what Liam was doing) because they were giving me errors.

Thanks! I couldn't have pulled that off without this page! PS: Sorry I don't know how you're getting your statements formatted with colors. etc.

You can use CTE also like below.

With cte as
(select Activity, SUM(Amount) as "Total Amount 2009"
   from Activities, Incomes
  where Activities.UnitName = ? AND
        Incomes.ActivityId = Activities.ActivityID
  GROUP BY Activity
),
cte1 as 
(select Activity, SUM(Amount) as "Total Amount 2008"
   from Activities, Incomes2008
  where Activities.UnitName = ? AND
        Incomes2008.ActivityId = Activities.ActivityID
  GROUP BY Activity
)
Select cte.Activity, cte.[Total Amount 2009] ,cte1.[Total Amount 2008]      
  from cte join cte1 ON cte.ActivityId = cte1.ActivityID
 WHERE a.UnitName = ?
 ORDER BY cte.Activity 

perhaps not the most elegant way to solve this

select  Activity, 
        SUM(Amount) as "Total_Amount",
        2009 AS INCOME_YEAR
from    Activities, Incomes
where Activities.UnitName = ? AND
      Incomes.ActivityId = Activities.ActivityID
GROUP BY Activity
ORDER BY Activity;

UNION

select  Activity, 
        SUM(Amount) as "Total_Amount",
        2008 AS INCOME_YEAR
from Activities, Incomes2008
where Activities.UnitName = ? AND
      Incomes2008.ActivityId = Activities.ActivityID
GROUP BY Activity
ORDER BY Activity;