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So I tried using join() after splitting a string into words and punctuation but it joins the string with a space in between the word and punctuation.
b = ['Hello', ',', 'who', 'are', 'you', '?']
c = " ".join(b)
But that returns:c = 'Hello , who are you ?'
and I want:c = 'Hello, who are you?'
688
findall() method to split a string into words and punctuation, e.g. result = re. findall(r"[\w'\"]+|[,.!?] ", my_str) . The findall() method will split the string on whitespace characters and punctuation and will return a list of the matches.
Python String split() Method A string can be split into substrings using the split(param) method. This method is part of the string object. The parameter is optional, but you can split on a specific string or character. Given a sentence, the string can be split into words.
The simplest approach provided by Python to convert the given list of Sentences into words with separate indices is to use split() method. This method split a string into a list where each word is a list item.
You could join on the punctuation first:
def join_punctuation(seq, characters='.,;?!'):
characters = set(characters)
seq = iter(seq)
current = next(seq)
for nxt in seq:
if nxt in characters:
current += nxt
else:
yield current
current = nxt
yield current
c = ' '.join(join_punctuation(b))
The join_punctuation generator yields strings with any following punctuation already joined on:
>>> b = ['Hello', ',', 'who', 'are', 'you', '?']
>>> list(join_punctuation(b))
['Hello,', 'who', 'are', 'you?']
>>> ' '.join(join_punctuation(b))
'Hello, who are you?'
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