I'm currently using Jersey as a proxy REST api to call another RESTful web service. Some of the calls will be passed to and from with minimal processing in my server.
Is there a way to do this cleanly? I was thinking of using the Jersey Client to make the REST call, then converting the ClientResponse into a Response. Is this possible or is there a better way to do this?
Some example code:
@GET
@Path("/groups/{ownerID}")
@Produces("application/xml")
public String getDomainGroups(@PathParam("ownerID") String ownerID) {
WebResource r = client.resource(URL_BASE + "/" + URL_GET_GROUPS + "/" + ownerID);
String resp = r.get(String.class);
return resp;
}
This works if the response is always a success, but if there's a 404 on the other server, I'd have to check the response code. In other words, is there clean way to just return the response I got?
There is no convenience method as far as I am aware. You can do this:
public Response getDomainGroups(@PathParam("ownerID") String ownerID) {
WebResource r = client.resource(URL_BASE + "/" + URL_GET_GROUPS + "/" + ownerID);
ClientResponse resp = r.get(ClientResponse.class);
return clientResponseToResponse(resp);
}
public static Response clientResponseToResponse(ClientResponse r) {
// copy the status code
ResponseBuilder rb = Response.status(r.getStatus());
// copy all the headers
for (Entry<String, List<String>> entry : r.getHeaders().entrySet()) {
for (String value : entry.getValue()) {
rb.header(entry.getKey(), value);
}
}
// copy the entity
rb.entity(r.getEntityInputStream());
// return the response
return rb.build();
}
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