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I tried to calculate the difference between two dates and I noticed one thing. When calculating only the days, the start of daylight saving time is included in the interval, so the result will be shorter with 1 day.
To obtain accurate results, the value of hours also must be considered.
For example:
SimpleDateFormat format = new SimpleDateFormat("MM-dd-yyyy");
Date dfrom = format.parse("03-29-2015");
Date dto = format.parse("03-30-2015");
long diff = dto.getTime() - dfrom.getTime();
System.out.println(diff);
System.out.println("Days: "+diff / (24 * 60 * 60 * 1000));
System.out.println("Hours: "+diff / (60 * 60 * 1000) % 24);
Output:
82800000
Days: 0
Hours: 23
Does anybody have a better solution?
461
The minusDays() method of LocalDate class in Java is used to subtract the number of specified day from this LocalDate and return a copy of LocalDate. For example, 2019-01-01 minus one day would result in 2018-12-31.
In Java, two dates can be compared using the compareTo() method of Comparable interface. This method returns '0' if both the dates are equal, it returns a value "greater than 0" if date1 is after date2 and it returns a value "less than 0" if date1 is before date2.
In Java 8, we can use ChronoUnit. DAYS. between(from, to) to calculate days between two dates.
Oh yes a better solution there is!
Stop using the outmoded java.util.Date class and embrace the power of the java.time API built into Java 8 and later (tutorial). Specifically, the DateTimeFormatter, LocalDate, and ChronoUnit classes.
DateTimeFormatter formatter = DateTimeFormatter.ofPattern("MM-dd-yyyy");
LocalDate date1 = LocalDate.parse("03-29-2015", formatter);
LocalDate date2 = LocalDate.parse("03-30-2015", formatter);
long days = ChronoUnit.DAYS.between(date1, date2);
System.out.println(days); // prints 1
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