I am using JavaScriptSerializer
for serializing DateTime, but when I deserialize it show one day less from the date it get serialize:
Here is test:
DateTime startDate=new DateTime(2012,1,20);//set the 20th of January
JavaScriptSerializer serializer=new JavaScriptSerializer();
string serializeDate= serializer.Serialize(startDate);
DateTime afterDeserialize= serializer.Deserialize<DateTime>(serializeDate);//I get 19th of Jan
Assert.Equals(startDate, afterDeserialize);
firstly I thougt it because of javascript datetime format but as I know for javascript Month is zero index 0=January
, but I am getting one day less than the original date.
It's not losing a day arbitrarily, it's converting to a UTC date (or I should say using the date in a UTC date format) so when it's unserialized it you're no longer within your personal time zone. It's basically performing:
DateTime whateverDate = /* incoming date */;
long ticks = whateverDate.ToUniversalTime() // make UTC
.Subtract(new DateTime(1970, 1, 1)) // subtract UNIX Epoch
.TotalMilliseconds(); // get milliseconds since then
// push in to the "\/Date(ticks)\/" format
String value = String.Format(@"\/Date({0})\/", ticks);
However, try the following:
// or you rely on it serializing, then bring it back to your own local time
// (apply the time zone).
afterDeserialize = afterDeserialize.ToLocalTime();
You'll now have the UTC time back to your local time (with time zone applied).
To Pass your test:
DateTime startDate = new DateTime(2012,1,20);
JavaScriptSerializer serializer = new JavaScriptSerializer();
String serializeDate = serializer.Serialize(startDate);
DateTime afterDeserialize = serializer.Deserialize<DateTime>(serializeDate)
.ToLocalTime(); // Note: this is added
Assert.Equals(startDate, afterDeserialize); // pass!
I had the same problem and solved it by using
Newtonsoft.Json.JsonConvert.SerializeObject()
instead of
new System.Web.Script.Serialization.JavaScriptSerializer().Serialize().
The latter call stores your DateTime converted to some random timezone (GMT+0 seems to be hardcoded).
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