Is there any simple way to check if first and last character of a string are the same or not, only with regex?
I know you can check with charAt
var firstChar = str.charAt(0);
var lastChar = str.charAt(length-1);
console.log(firstChar===lastChar):
I'm not asking for this : Regular Expression to match first and last character
To match a character having special meaning in regex, you need to use a escape sequence prefix with a backslash ( \ ). E.g., \. matches "." ; regex \+ matches "+" ; and regex \( matches "(" . You also need to use regex \\ to match "\" (back-slash).
Literal Characters and Sequences For instance, you might need to search for a dollar sign ("$") as part of a price list, or in a computer program as part of a variable name. Since the dollar sign is a metacharacter which means "end of line" in regex, you must escape it with a backslash to use it literally.
Basically (0+1)* mathes any sequence of ones and zeroes. So, in your example (0+1)*1(0+1)* should match any sequence that has 1. It would not match 000 , but it would match 010 , 1 , 111 etc. (0+1) means 0 OR 1.
match() is an inbuilt function in JavaScript used to search a string for a match against any regular expression. If the match is found, then this will return the match as an array. Parameters: Here the parameter is “regExp” (i.e. regular expression) which will compare with the given string.
You can use regex with capturing group and its backreference to assert both starting and ending characters are same by capturing the first caharacter. To test the regex match use RegExp#test
method.
var regex = /^(.).*\1$/;
console.log(
regex.test('abcdsa')
)
console.log(
regex.test('abcdsaasaw')
)
Regex explanation here :
^
asserts position at start of the string(.)
.*
matches any character (except newline) - between zero and unlimited times, as many times as possible, giving back as needed (greedy)\1
matches the same text as most recently matched by the 1st capturing group$
asserts position at the end of the stringThe .
doesn't include newline character, in order include newline update the regex.
var regex = /^([\s\S])[\s\S]*\1$/;
console.log(
regex.test(`abcd
sa`)
)
console.log(
regex.test(`ab
c
dsaasaw`)
)
Refer : How to use JavaScript regex over multiple lines?
Regex explanation here :
[.....]
- Match a single character present\s
- matches any whitespace character (equal to [\r\n\t\f\v ]
)\S
- matches any non-whitespace character (equal to [^\r\n\t\f ]
)finally [\s\S]
is matches any character.
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