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I would like to have a regex which matches the string with NO whitespace(s) at the beginning. But the string containing whitespace(s) in the middle CAN match. So far i have tried below
[^-\s][a-zA-Z0-9-_\\s]+$
Debuggex Demo
Above is not allowing whitespace(s) at the beginning, but also not allowing in the middle/end of the string. Please help me.
717
The replaceAll() method accepts a string and a regular expression replaces the matched characters with the given string. To remove all the white spaces from an input string, invoke the replaceAll() method on it bypassing the above mentioned regular expression and an empty string as inputs.
Turn on free-spacing mode to ignore whitespace between regex tokens and allow # comments. Turn on free-spacing mode to ignore whitespace between regex tokens and allow # comments, both inside and outside character classes.
The \S metacharacter matches non-whitespace characters. Whitespace characters can be: A space character.
The RegExp \D Metacharacter in JavaScript is used to search non digit characters i.e all the characters except digits. It is same as [^0-9]. Example 1: This example searches the non-digit characters in the whole string.
In your 2nd character class, \\s will match \ and s, and not \s. Thus it doesn't matches a whitespace. You should use just \s there. Also, move the hyphen towards the end, else it will create unintentional range in character class:
^[^-\s][a-zA-Z0-9_\s-]+$
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