I was very surprised that I didn't find this already on the internet. is there's a regular expression that validates only digits in a string including those starting with 0 and not white spaces
here's the example I'm using
  function ValidateNumber() {
  var regExp = new RegExp("/^\d+$/");
  var strNumber = "010099914934";
  var isValid = regExp.test(strNumber);
  return isValid;
}
but still the isValid value is set to false
You could use /^\d+$/.
That means:
^ string start\d+ a digit, once or more times$ string endThis way you force the match to only numbers from start to end of that string.
Example here: https://regex101.com/r/jP4sN1/1
jsFiddle here: https://jsfiddle.net/gvqzknwk/
If you are using the RegExp constructor you need to double escape the \ in the \d selector, so your string passed to the RegExp constructor must be "^\\d+$".
So your function could be:
function ValidateNumber(strNumber) {
    var regExp = new RegExp("^\\d+$");
    var isValid = regExp.test(strNumber); // or just: /^\d+$/.test(strNumber);
    return isValid;
}
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