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Javascript Radix Sort

I have been looking around the web for a while and I am wondering if there is a 'stable' defacto implementation of Radix Sort that is generally used?

Two classifications of radix sorts are least significant digit (LSD) radix sorts and most significant digit (MSD) radix sorts.

Looking for an example of LSD or MSD.

like image 711
BendYourTaxes Avatar asked Apr 09 '16 06:04

BendYourTaxes


1 Answers

My version is more verbose, but executes quickly even for large number of items:

  var testArray = [ 331, 454, 230, 34, 343, 45, 59, 453, 345, 231, 9 ];

  function radixBucketSort (arr) {
    var idx1, idx2, idx3, len1, len2, radix, radixKey;
    var radices = {}, buckets = {}, num, curr;
    var currLen, radixStr, currBucket;

    len1 = arr.length;
    len2 = 10;  // radix sort uses ten buckets

    // find the relevant radices to process for efficiency        
    for (idx1 = 0;idx1 < len1;idx1++) {
      radices[arr[idx1].toString().length] = 0;
    }
    
    // loop for each radix. For each radix we put all the items
    // in buckets, and then pull them out of the buckets.
    for (radix in radices) {          
      // put each array item in a bucket based on its radix value
      len1 = arr.length;
      for (idx1 = 0;idx1 < len1;idx1++) {
        curr = arr[idx1];
        // item length is used to find its current radix value
        currLen = curr.toString().length;
        // only put the item in a radix bucket if the item
        // key is as long as the radix
        if (currLen >= radix) {
          // radix starts from beginning of key, so need to
          // adjust to get redix values from start of stringified key
          radixKey = curr.toString()[currLen - radix];
          // create the bucket if it does not already exist
          if (!buckets.hasOwnProperty(radixKey)) {
            buckets[radixKey] = [];
          }
          // put the array value in the bucket
          buckets[radixKey].push(curr);          
        } else {
          if (!buckets.hasOwnProperty('0')) {
            buckets['0'] = [];
          }
          buckets['0'].push(curr);          
        }
      }
      // for current radix, items are in buckets, now put them
      // back in the array based on their buckets
      // this index moves us through the array as we insert items
      idx1 = 0;
      // go through all the buckets
      for (idx2 = 0;idx2 < len2;idx2++) {
        // only process buckets with items
        if (buckets[idx2] != null) {
          currBucket = buckets[idx2];
          // insert all bucket items into array
          len1 = currBucket.length;
          for (idx3 = 0;idx3 < len1;idx3++) {
            arr[idx1++] = currBucket[idx3];
          }
        }
      }
      buckets = {};
    }
  }
  radixBucketSort(testArray);
  console.log(testArray);          
like image 169
Greg Lafrance Avatar answered Sep 20 '22 10:09

Greg Lafrance