I have a set of string numbers having decimals, for example: 23.456
, 9.450
, 123.01
... I need to retrieve the number of decimals for each number, knowing that they have at least 1 decimal.
In other words, the retr_dec()
method should return the following:
retr_dec("23.456") -> 3 retr_dec("9.450") -> 3 retr_dec("123.01") -> 2
Trailing zeros do count as a decimal in this case, unlike in this related question.
Is there an easy/delivered method to achieve this in Javascript or should I compute the decimal point position and compute the difference with the string length? Thanks
You can check like below, String decimalPoint = '1.23'; Boolean isValidDecimal = true; if(decimalPoint != null){ try{ Decimal. valueOf(decimalPoint); } catch(TypeException e){ isValidDecimal = false; } } system.
An alternative approach is to use the modulo operator. Use the modulo (%) operator to get the decimal part of a number, e.g. const decimal = num % 1 . When used with a divisor of 1 , the modulo operator returns the decimal part of the number.
floor( ). Math. abs( ): The Math. abs() function in JavaScript is used to return the absolute value of a number.
To get the decimal part you could do this: double original = 1.432d; double decimal = original % 1d; Note that due to the way that decimals are actually thought of, this might kill any precision you were after.
function decimalPlaces(num) { var match = (''+num).match(/(?:\.(\d+))?(?:[eE]([+-]?\d+))?$/); if (!match) { return 0; } return Math.max( 0, // Number of digits right of decimal point. (match[1] ? match[1].length : 0) // Adjust for scientific notation. - (match[2] ? +match[2] : 0)); }
The extra complexity is to handle scientific notation so
decimalPlaces('.05') 2 decimalPlaces('.5') 1 decimalPlaces('1') 0 decimalPlaces('25e-100') 100 decimalPlaces('2.5e-99') 100 decimalPlaces('.5e1') 0 decimalPlaces('.25e1') 1
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