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I have some zeros prior to a positive integer. I want to remove the zeros so only the positive integer remains. Like '001' will only be '1'. I thought the easiest way was to use parseInt('001'). But what I discovered is that it don't works for the number 8 and 9. Example parseInt('008') will result in '0' instead of '8'.
Here are the whole html code:
<html> <body>
<script>
var integer = parseInt('002');
document.write(integer);
</script>
</body> </html>
But can I somehow report this problem? Do anyone know an another easy workaround this problem?
685
The parseInt function parses a string argument and returns a number with the leading zeros removed.
The parseInt function converts its first argument to a string, parses that string, then returns an integer or NaN . If not NaN , the return value will be the integer that is the first argument taken as a number in the specified radix .
parseInt() doesn't always correctly convert to integer In JavaScript, all numbers are floating point. Integers are floating point numbers without a fraction. Converting a number n to an integer means finding the integer that is “closest” to n (where “closest” is a matter of definition).
parseFloat( ) parseFloat() is quite similar to parseInt() , with two main differences. First, unlike parseInt() , parseFloat() does not take a radix as an argument. This means that string must represent a floating-point number in decimal form (radix 10), not octal (radix 8) or hexadecimal (radix 6).
The range of int is between Integer. MAX_VALUE and Integer. MIN_VALUE inclusive (i.e. from 2147483647 down to -2147483648). You cannot parse the int value of out that range.
You have to specify the base of the number (radix)
parseInt('01', 10);
This is documented behavior: http://www.w3schools.com/jsref/jsref_parseInt.asp
Strings with a leading '0' are parsed as if they were octal.
28
Number prefixed with zero is parsed as octal.
26
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