Javascript compare 3 values

Question

I have 3 values that I want to compare f, g and h. I have some code to check that they all equal each other and that none of them are null. I've had a look online but could not find anything that seemed to answer my query. Currently I am checking the code in the following way...

if(g == h && g == f && f == h && g != null && f != null && h != null) { //do something } 

This is quite long winded and I might be adding more values, so I was just wondering if there is a quicker way to check that none of the values are null and that all the values equal each other?

Thanks in advance for any help.

Answer 1

You could shorten that to

if(g === h && g === f && g !== null) { //do something } 

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For an actual way to compare multiple values (regardless of their number)
(inspired by/ simplified @Rohan Prabhu answer)

function areEqual(){    var len = arguments.length;    for (var i = 1; i< len; i++){       if (arguments[i] === null || arguments[i] !== arguments[i-1])          return false;    }    return true; } 

and call this with

if( areEqual(a,b,c,d,e,f,g,h) ) { //do something } 

Answer 2

What about

(new Set([a,b,c])).size === 1