Javascript closure

Question

Here is a code

var collection = (function (){
                var x = 0;
                return {
                    y : x,
                    get : function(){return x},
                    set : function(n) { x = n}                        
                }
              }());

collection.set(1000);

Why collection.y != collection.get() ?

Answer 1

y is not a "pointer" to x. When created the closure you simply copied the value of x at that moment into y, and every time you call get()/set() you only operate on x (no relation to y)

Answer 2

You are not setting collection y when you call collection.set(1000)

Answer 3

Because y will store the value 0, and will not read it from x. While get() will read the variable x every time you call it.