Java ZIP - how to unzip folder?

Question

Is there any sample code, how to particaly unzip folder from ZIP into my desired directory? I have read all files from folder "FOLDER" into byte array, how do I recreate from its file structure?

Answer 1

I am not sure what do you mean by particaly? Do you mean do it yourself without of API help?

In the case you don't mind using some opensource library, there is a cool API for that out there called zip4J

It is easy to use and I think there is good feedback about it. See this example:

String source = "folder/source.zip"; String destination = "folder/source/";     try {     ZipFile zipFile = new ZipFile(source);     zipFile.extractAll(destination); } catch (ZipException e) {     e.printStackTrace(); } 

If the files you want to unzip have passwords, you can try this:

String source = "folder/source.zip"; String destination = "folder/source/"; String password = "password";  try {     ZipFile zipFile = new ZipFile(source);     if (zipFile.isEncrypted()) {         zipFile.setPassword(password);     }     zipFile.extractAll(destination); } catch (ZipException e) {     e.printStackTrace(); } 

I hope this is useful.