I have a java project that is using two imported jars with the same class (com.sun.mail.imap.IMAPFolder
). Is there a way to explicitly say which jar to use when importing the class? Using:
import com.sun.mail.imap.IMAPFolder;
would seem to use the class in order of build path order but this does not seem to be the case for some reason causing
Exception in thread "main" java.lang.reflect.InvocationTargetException
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:57)
at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43)
at java.lang.reflect.Method.invoke(Method.java:616)
at org.eclipse.jdt.internal.jarinjarloader.JarRsrcLoader.main(JarRsrcLoader.java:58)
Caused by: java.lang.NoSuchMethodError: com.sun.mail.imap.IMAPFolder.idle()V
at com.woodbury.GCM.HelperGmailMonitor.doEmail(HelperGmailMonitor.java:104)
at com.woodbury.GCM.Launch.listen(Launch.java:16)
at com.woodbury.GCM.Launch.main(Launch.java:10)
... 5 more
at runtime. I am building the project in eclipse.
Depending on your system settings, you should be able to just double click the jar file to run it, or right-click and select to run it. Then the tool will prompt for the two files to compare.
Note that you can't import two classes with the same name in two different packages. The classes Integer and String belongs to the package java. lang but they don't need to be imported as the java.
To run an application in a nonexecutable JAR file, we have to use -cp option instead of -jar. We'll use the -cp option (short for classpath) to specify the JAR file that contains the class file we want to execute: java -cp jar-file-name main-class-name [args …]
When a class is loaded, the first implementation that matches the requested fully qualified name that is visible to the relevant ClassLoader
is what gets returned. Any other implementations with the same fully qualified name are effectively hidden to that ClassLoader
.
What this means in a standard Java SE application is that the first code base (i.e. a jar) listed on the classpath with the required class, provides it, and all other code bases' implementations of the same fully qualified class are hidden.
Assume that A.jar contains the compiled class
package com.stackoverflow.example;
public class Hello {
public static String getGreeting(){
return "Hello, A!"
}
}
Assume that B.jar contains the compiled class
package com.stackoverflow.example
public class Hello {
public static String getGreeting(){
return "Hello, B!"
}
}
Note that in both of the above classes have the same fully qualified name.
Assume main class is
import com.stackoverflow.example.Hello;
public class ExampleMain {
public static void main(String[] args){
System.out.println(Hello.getGreeting());
}
}
If I were to invoke my program with
java -cp A.jar:B.jar ExampleMain
the output is: Hello, A!
If I reverse the classpath like so
java -cp B.jar:A.jar ExampleMain
the output is: Hello, B!
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