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A parallel stream is performed one or more elements at a time. Thus the map() would preserve the encounter of the stream order but not the original List's order.
No, it will never change (unless you explicitely change it yourself). What you have written corresponds to a Stream pipeline and a single pipeline has a single orientation: parallel or sequential.
collect() is one of the Java 8's Stream API's terminal methods. It allows us to perform mutable fold operations (repackaging elements to some data structures and applying some additional logic, concatenating them, etc.) on data elements held in a Stream instance.
You obtain a stream from a collection by calling the stream() method of the given collection. Here is an example of obtaining a stream from a collection: List<String> items = new ArrayList<String>(); items.
Yes, you can expect this even if you are using parallel stream as long as you did not explicitly convert it into unordered() mode.
The ordering never changes in sequential mode, but may change in parallel mode. The stream becomes unordered either:
unordered() callHashSet stream is unordered as order is implementation dependent and you cannot rely on it)forEach() operation or collecting to unordered collector like toSet())In your case none of these conditions met, thus your stream is ordered.
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