Java sort string both alphabetically and keep ASCII order

Question

The list is: Arrays.asList("Za", "ab", "AB", "Sa", "1ab", "Ab", "!Ab");

If I use stream().sorted() then the order is: !Ab 1ab AB Ab Za ab --> Za should not be in front of ab.

If I use sorted(String.CASE_INSENSITIVE_ORDER) then the order is !Ab 1ab ab AB Ab Za --> This time, AB is behind ab.

Is there any way to combine the two rules so we have list sorted alphabetically and uppercase is greater than lower case?

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Added Example: 1AB - A0B - AbD - aBD - abd1 - ZAB Sorted alphabetically (Z is never in front of a) and Number > Uppercase > Lowercase (AbD > aBD)

Answer 1

The problem is that ab and AB are equal; hence themselves are unordered in the result. So add a normal comparison, as capitals come before small letters.

list.stream()
    .sorted(String.CASE_INSENSITIVE_ORDER
            .thenComparing(Comparator.naturalOrder()))

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After comment

list.stream()
    .sorted(String.CASE_INSENSITIVE_ORDER
            .thenComparing(Comparator.reverseOrder()))