In java serialization class Mp3player extends ElectronicDevice implements Serializable in this code super class electronicdevice is not implemented serializable. here super class is also getting serialized. my understanding is super class is also gets serialized due to extends.let me know my understanding is correct or not.
import java.io.*;
class ElectronicDevice {
ElectronicDevice()
{
System.out.print("ed ");
}
}
class Mp3player extends ElectronicDevice implements Serializable {
Mp3player()
{
System.out.print("mp ");
}
}
class MiniPlayer extends Mp3player {
MiniPlayer()
{
System.out.print("mini ");
}
public static void main(String[] args) {
MiniPlayer m = new MiniPlayer();
try {
FileOutputStream fos = new FileOutputStream("dev.txt");
ObjectOutputStream os = new ObjectOutputStream(fos);
os.writeObject(m); os.close();
FileInputStream fis = new FileInputStream("dev.txt");
ObjectInputStream is = new ObjectInputStream(fis);
MiniPlayer m2 = (MiniPlayer) is.readObject();
is.close();
System.out.println();
} catch (Exception x) {
System.out.print("x ");
}
}
}
No.During the process of serialization only the fields of Serializable objects are written out and restored.
According to javadocs
During deserialization, the fields of non-serializable classes will be initialized using the public or protected no-arg constructor of the class.
Where as the fields of serializable subclasses will be restored from the stream.
Please look into this example
Here ElectronicDevice
is not Serializable
,where as Mp3player
is Serializable
.Observe the fields of respected classes behaviour in serialization process.
import java.io.*;
class ElectronicDevice {
public int i = 0;
protected ElectronicDevice()
{
System.out.println("ed ");
}
}
class Mp3player extends ElectronicDevice implements Serializable {
int j =0;
Mp3player()
{
System.out.println("mp ");
}
}
class MiniPlayer extends Mp3player {
MiniPlayer()
{
System.out.println("mini ");
}
public static void main(String[] args) {
MiniPlayer m = new MiniPlayer();
m.i = 30;
m.j = 40;
try {
System.out.println("i value before serialization: "+m.i);//prints 30
System.out.println("i value before serialization: "+m.j);//prints 40
FileOutputStream fos = new FileOutputStream("dev.txt");
ObjectOutputStream os = new ObjectOutputStream(fos);
os.writeObject(m); os.close();
FileInputStream fis = new FileInputStream("dev.txt");
ObjectInputStream is = new ObjectInputStream(fis);
MiniPlayer m2 = (MiniPlayer) is.readObject();
is.close();
System.out.println("i value after serialization: "+m2.i);//prints o
System.out.println("j value after serialization: "+m2.j);//prints 40
System.out.println();
} catch (Exception x) {
x.printStackTrace();
System.out.print("x ");
}
}
}
Since super class doesn't implement Serializable contents of the super class wont get serialized. Only the contents of the subclass would get serialized. When you deserialize the default constructor of the superclass would get executed and the fields of the superclass initialized as if you invoked the default constructor.
Following example illustrates this.
public class SerializationTest {
public static class Base {
private String name;
public Base() {
this.name = "johnDow";
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
}
public static class Sub extends Base implements Serializable {
private static final long serialVersionUID = 1L;
private String age;
public String getAge() {
return age;
}
public void setAge(String age) {
this.age = age;
}
}
public static void main(String[] args) throws Exception {
ByteArrayOutputStream byteArrayOS = new ByteArrayOutputStream();
ObjectOutputStream out = new ObjectOutputStream(byteArrayOS);
Sub s = new Sub();
s.setName("name");
s.setAge("10");
out.writeObject(s);
ObjectInputStream ois = new ObjectInputStream(new ByteArrayInputStream(byteArrayOS.toByteArray()));
Sub d = (Sub) ois.readObject();
System.out.println(d.getName() + "-" + d.getAge());
}
}
What gets printed is
johnDow-10
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