Java: round to nearest multiple of 5 (either up or down)

Question

haven't tested it, but 5*(Math.round(f/5)); should work

Nearest Multiple of 5 for Upper value

5*(Math.ceil(Math.abs(number/5)));

for Lower Value

5*(Math.floor(Math.abs(number/5)));

it gives Positive value only.

How about something like this:

return round((number/5))*5;

public static void main(String args[]) {
    double num = 67.5;
    if (num % 5 == 0)
        System.out.println("OK");
    else if (num % 5 < 2.5)
        num = num - num % 5;
    else
        num = num + (5 - num % 5);
    System.out.println(num);

}

Try this.

Gefei's solution is working, but I had to convert explicitly to double like this: 5*(Math.round((double)f/5))

There are many other solutions on this page, but I believe this is the most concise one.

To find the closest multiple of x for a given number,

let x be the multiple and num be the given number:

// The closest multiple of x <= num
int multipleOfX = x * ( num / x );

In your case:

int multipleOf5 = 5 * ( num / 5 );