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java regex split string

I'm kind of stuck trying to come up with regular expression to break up strings with the following properties:

  1. Delimited by the | (pipe) character
  2. If an individual value contains a pipe, escaped with \ (backslash)
  3. If an individual value ends with backslash, escaped with backslash

So for example, here are some strings that I want to break up:

  1. One|Two|Three should yield: ["One", "Two", "Three"]
  2. One\|Two\|Three should yield: ["One|Two|Three"]
  3. One\\|Two\|Three should yield: ["One\", "Two|Three"]

Now how could I split this up with a single regex?

UPDATE: As many of you already suggested, this is not a good application of regex. Also, the regex solution is orders of magnitude slower than just iterating over the characters. I ended up iterating over the characters:

public static List<String> splitValues(String val) {
    final List<String> list = new ArrayList<String>();
    boolean esc = false;
    final StringBuilder sb = new StringBuilder(1024);
    final CharacterIterator it = new StringCharacterIterator(val);
    for(char c = it.first(); c != CharacterIterator.DONE; c = it.next()) {
        if(esc) {
            sb.append(c);
            esc = false;
        } else if(c == '\\') {
            esc = true;
        } else if(c == '|') {
            list.add(sb.toString());
            sb.delete(0, sb.length());
        } else {
            sb.append(c);
        }
    }
    if(sb.length() > 0) {
        list.add(sb.toString());
    }
    return list;
}
like image 837
Mohamed Nuur Avatar asked Jul 29 '11 22:07

Mohamed Nuur


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1 Answers

The trick is not to use the split() method. That forces you to use a lookbehind to detect escaped characters, but that fails when the escapes are themselves escaped (as you've discovered). You need to use find() instead, to match the tokens instead of the delimiters:

public static List<String> splitIt(String source)
{
  Pattern p = Pattern.compile("(?:[^|\\\\]|\\\\.)+");
  Matcher m = p.matcher(source);
  List<String> result = new ArrayList<String>();
  while (m.find())
  {
    result.add(m.group().replaceAll("\\\\(.)", "$1"));
  }
  return result;
}

public static void main(String[] args) throws Exception
{
  String[] test = { "One|Two|Three", 
                    "One\\|Two\\|Three", 
                    "One\\\\|Two\\|Three", 
                    "One\\\\\\|Two" };
  for (String s :test)
  {
    System.out.printf("%n%s%n%s%n", s, splitIt(s));
  }
}

output:

One|Two|Three
[One, Two, Three]

One\|Two\|Three
[One|Two|Three]

One\\|Two\|Three
[One\, Two|Three]

One\\\|Two
[One\|Two]
like image 142
Alan Moore Avatar answered Oct 06 '22 19:10

Alan Moore