I need some help. Im getting:
Caused by: java.util.regex.PatternSyntaxException: Unclosed character class near index 24
^[a-zA-Z└- 0-9£µ /.'-\]*$
^
at java.util.regex.Pattern.error(Pattern.java:1713)
at java.util.regex.Pattern.clazz(Pattern.java:2254)
at java.util.regex.Pattern.sequence(Pattern.java:1818)
at java.util.regex.Pattern.expr(Pattern.java:1752)
at java.util.regex.Pattern.compile(Pattern.java:1460)
at java.util.regex.Pattern.<init>(Pattern.java:1133)
at java.util.regex.Pattern.compile(Pattern.java:823)
Here is my code:
String testString = value.toString();
Pattern pattern = Pattern.compile("^[a-zA-Z\300-\3770-9\u0153\346 \u002F.'-\\]*$");
Matcher m = pattern.matcher(testString);
I have to use the unicode value for some because I'm working with xhtml.
Any help would be great!
Assuming that you want to match \
and -
and not ]
:
Pattern pattern = Pattern.compile("^[a-zA-Z\300-\3770-9\u0153\346 \u002F.'\\\\-]*$");
You need to double escape your backslashes, as \
is also an escape character in regex. Thus \\]
escapes the backslash for java but not for regex. You need to add another java-escaped \
in order to regex-escape your second java-escaped \
.
So \\\\
after java escaping becomes \\
which is then regex escaped to \
.
Moving -
to the end of the sequence means that it is used as a character, instead of a range operator as pointed out by Pshemo.
It is hard to say what are you trying to achieve, but I can see few strange things in your regex:
\\]
which makes ]
normal character.
]
in your characters class then you need additional ]
at the end, like "^[a-zA-Z\300-\3770-9\u0153\346 \u002F.'-\\]]*$"
\
in your characters class then you need to use \\\\
version, because you need to escape its special meaning two times, in regex engine, and in Javas String-
with ('-\\]
) which in character class is used to specify range of characters like a-z
or A-Z
. To escape its special meaning you need to use \\-
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