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should be simple, but I'm going crazy with it.
Given a text like:
line number 1
line number 2
line number 2A
line number 3
line number 3A
line number 3B
line number 4
I need the Java regex that deletes the line terminators then the new line begin with space, so that the sample text above become:
line number 1
line number 2line number 2A
line number 3line number 3Aline number 3B
line number 4
228
\s stands for “whitespace character”. Again, which characters this actually includes, depends on the regex flavor. In all flavors discussed in this tutorial, it includes [ \t\r\n\f]. That is: \s matches a space, a tab, a carriage return, a line feed, or a form feed.
To match a literal space, you'll need to escape it: "\\ " . This is a useful way of describing complex regular expressions: phone <- regex(" \\(? #
Therefore, the regular expression \s matches a single whitespace character, while \s+ will match one or more whitespace characters.
Use String. trim() method to get rid of whitespaces (spaces, new lines etc.) from the beginning and end of the string.
String res = orig.replaceAll("[\\r\\n]+\\s", "");
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