I'm using the javax.persistence
package to map my Java classes.
I have entities like these:
public class UserEntity extends IdEntity {
}
which extends a mapped superclass named IdEntity
:
@MappedSuperclass
public class IdEntity extends VersionEntity {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
private Integer id;
// Getters and setters below...
}
The IdEntity
super class extends another mapped super class named VersionEntity
to make all entities inherit version properties:
@MappedSuperclass
public abstract class VersionEntity {
@Version
private Integer version;
// Getters and setters below...
}
Why?
Because now I can make generic queries on the IdEntity class for all entities, and it will look like this: (example)
CriteriaBuilder builder = JPA.em().getCriteriaBuilder();
CriteriaQuery<IdEntity> criteria = builder.createQuery(IdEntity.class);
Now to the problem.
Some of my entities will have timestamps like created_at
and deleted_at
. But not all entities.
I could provide these properties in my entity classes like this:
public class UserEntity extends IdEntity {
@Basic(optional = false)
@Column(name = "updated_at")
@Temporal(TemporalType.TIMESTAMP)
private Date updatedAt;
}
But as I have a lot of entities, this will make me put a lot of redundant code in all entities that should have timestamps. I wish there was some way I could make the relevant classes inherit these fields in some way.
One possible solution is to create a parallell IdEntity
superclass, maybe named IdAndTimeStampEntity
and make those entities that should have timestamps inherit from this new superclass instead, but hey that's not fair to my colleague-developers because now they have to know which super class to choose from when writing generic queries:
CriteriaBuilder builder = JPA.em().getCriteriaBuilder();
CriteriaQuery<???> criteria = builder.createQuery(???); // Hmm which entity should I choose IdEntity or IdAndTimeStampEntity ?? *Annoyed*
And the generic entity queries become not so generic..
My question: How can I make
all
of my entities inheritid
andversion
fields, but only a sub part of all entities inherit timestamp fields, but keep my queries to a single type of entities?
Question from Bolzano: "can you add the code which you specify the path(holds table info) for entities ?"
Here is a working example of querying a UserEntity
which is a IdEntity
CriteriaBuilder builder = JPA.em().getCriteriaBuilder();
CriteriaQuery<IdEntity> criteria = builder.createQuery(IdEntity.class);
Root<IdEntity> from = criteria.from(IdEntity.class);
criteria.select(from);
Path<Integer> idPath = from.get(UserEntity_.id); //generated meta model
criteria.where(builder.in(idPath).value(id));
TypedQuery<IdEntity> query = JPA.em().createQuery(criteria);
return query.getSingleResult();
A mapped superclass is a special type of class that is not persistent itself, but has subclasses that are persistent. A mapped superclass is useful for defined a common persistence superclass that defines common behavior across a set of classes, such as an id or version attribute.
Annotation Type MappedSuperclass @Documented @Target(value=TYPE) @Retention(value=RUNTIME) public @interface MappedSuperclass. Designates a class whose mapping information is applied to the entities that inherit from it. A mapped superclass has no separate table defined for it.
JPA Inheritence Overview Inheritence is a key feature of object-oriented programming language in which a child class can acquire the properties of its parent class. This feature enhances reusability of the code. The relational database doesn't support the mechanism of inheritance.
Entities support class inheritance, polymorphic associations, and polymorphic queries. Entity classes can extend non-entity classes, and non-entity classes can extend entity classes.
I would pick a solution that didn't enforce a class-based object model like you've outlined. What happens when you don't need optimistic concurrency checking and no timestamps, or timestamps but no OCC, or the next semi-common piece of functionality you want to add? The permutations will become unmanageable.
I would add these common interactions as interfaces, and I would enhance your reusable find by id with generics to return the actual class you care about to the caller instead of the base superclass.
Note: I wrote this code in Stack Overflow. It may need some tweaking to compile.
@MappedSuperclass
public abstract class Persistable {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
private Integer id;
// getter/setter
}
public interface Versioned {
Integer getVersion();
}
public interface Timestamped {
Date getCreated();
Date getLastUpdated();
}
@Embeddable
public class TimestampedEntity {
@Column(name = "create_date")
@Temporal
private Date created;
@Column
@Temporal
private Date lastUpdated;
// getters/setters
}
@Entity
public class UserEntity extends Persistable implements Versioned, Timestamped {
@Version
private Integer version;
@Embedded
private TimestampedEntity timestamps;
/*
* interface-defined getters. getTimestamps() doesn't need to
* be exposed separately.
*/
}
public class <CriteriaHelperUtil> {
public <T extends Persistable> T getEntity(Class<T> clazz, Integer id, SingularAttribute idField) {
CriteriaBuilder builder = JPA.em().getCriteriaBuilder();
CriteriaQuery<T> criteria = builder.createQuery(clazz);
Root<T> from = criteria.from(clazz);
criteria.select(from);
Path<Integer> idPath = from.get(idField);
criteria.where(builder.in(idPath).value(id));
TypedQuery<T> query = JPA.em().createQuery(criteria);
return query.getSingleResult();
}
}
Basic Usage:
private UserEntity ue = CriteriaHelperUtil.getEntity(UserEntity.class, 1, UserEntity_.id);
ue.getId();
ue.getVersion();
ue.getCreated();
// FooEntity implements Persistable, Timestamped
private FooEntity fe = CriteriaHelperUtil.getEntity(FooEntity.class, 10, FooEntity_.id);
fe.getId();
fe.getCreated();
fe.getVersion(); // Compile Error!
@MappedSuperclass
public class IdEntity{
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
private Integer id;
@Version
private Integer version;
}
@MappedSuperclass
public class IdAndTimeStampEntity extends IdEntity{
Date created;
}
@Entity
public class UserEntity extends IdAndTimeStampEntity{
String name;
}
@Entity
public class FooEntity extends IdEntity{...
Pros of this solution:
In simple and clear way uses OOP without need to embed duplicate code implementing intefaces in every subclass. (Every class is also interface)
Optimistic locking version column is mostly used approach. And should be part of base class. Except read only entities like codetables.
Usage:
public <T extends IdEntity> T persist(T entity) {
if (entity instanceof IdAndTimeStampEntity) {
((IdAndTimeStampEntity) entity).setCreated(new Date());
}
if (!em.contains(entity) && entity.getId() != null) {
return em.merge(entity);
} else {
em.persist(entity);
return entity;
}
}
I wish there was some way I could make the relevant classes inherit these fields in some way.
You could make a custom annotation @Timed
and use an annotation processor to add the timestamp field and annotations, either by using a bytecode manipulation framework or creating a delegating subclass. Or, for example if you use Lombok, create a Lombok annotation.
That way, your team members only have to remember to use the @Timed
annotation when you have entities with timestamps. Whether you like such approach or not is up to you.
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