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Java: Outputting text file to Console

I'm attempting to output a text file to the console with Java. I was wondering what is the most efficient way of doing so?

I've researched several methods however, it's difficult to discern which is the least performance impacted solution.

Outputting a text file to the console would involve reading in each line in the file, then writing it to the console.

Is it better to use:

  1. Buffered Reader with a FileReader, reading in lines and doing a bunch of system.out.println calls?

    BufferedReader in = new BufferedReader(new FileReader("C:\\logs\\")); 
    while (in.readLine() != null) {
          System.out.println(blah blah blah);          
    }         
    in.close();
    
  2. Scanner reading each line in the file and doing system.print calls?

    while (scanner.hasNextLine()) { 
        System.out.println(blah blah blah);   
    }
    

Thanks.

like image 724
user459811 Avatar asked Oct 07 '10 22:10

user459811


2 Answers

If all you want to do is print the contents of a file (and don't want to print the next int/double/etc.) to the console then a BufferedReader is fine.

Your code as it is won't produce the result you're after, though. Try this instead:

BufferedReader in = new BufferedReader(new FileReader("C:\\logs\\log001.txt"));
String line = in.readLine();
while(line != null)
{
  System.out.println(line);
  line = in.readLine();
}
in.close();

I wouldn't get too hung up about it, though because it's more likely that the main bottleneck will be the ability of your console to print the information that Java is sending it.

like image 130
Catchwa Avatar answered Nov 13 '22 16:11

Catchwa


If you're not interested in the character based data the text file is containing, just stream it "raw" as bytes.

InputStream input = new BufferedInputStream(new FileInputStream("C:/logs.txt"));
byte[] buffer = new byte[8192];

try {
    for (int length = 0; (length = input.read(buffer)) != -1;) {
        System.out.write(buffer, 0, length);
    }
} finally {
    input.close();
}

This saves the cost of unnecessarily massaging between bytes and characters and also scanning and splitting on newlines and appending them once again.

As to the performance, you may find this article interesting. According the article, a FileChannel with a 256K byte array which is read through a wrapped ByteBuffer and written directly from the byte array is the fastest way.

FileInputStream input = new FileInputStream("C:/logs.txt");
FileChannel channel = input.getChannel();
byte[] buffer = new byte[256 * 1024];
ByteBuffer byteBuffer = ByteBuffer.wrap(buffer);

try {
    for (int length = 0; (length = channel.read(byteBuffer)) != -1;) {
        System.out.write(buffer, 0, length);
        byteBuffer.clear();
    }
} finally {
    input.close();
}
like image 4
BalusC Avatar answered Nov 13 '22 17:11

BalusC