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How to chain conditional statements in Java in a way that if b is false, than do not check c?
If a and c are false, and b is true, does c will be checked?
if (a || b || c)
I am looking for similar feature that PHP holds with difference between OR and ||
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In Java, parentheses() and Array subscript[] have the highest precedence in Java. For example, Addition and Subtraction have higher precedence than the Left shift and Right shift operators.
The logical-AND operator ( && ) has higher precedence than the logical-OR operator ( || ), so q && r is grouped as an operand.
Operator Precedence ¶ The precedence of an operator specifies how "tightly" it binds two expressions together. For example, in the expression 1 + 5 * 3 , the answer is 16 and not 18 because the multiplication ("*") operator has a higher precedence than the addition ("+") operator.
The Java || operator (logical or operator) does not evaluate additional arguments if the left operand is true. If you wanted to do that, you can use | (bitwise or operator), although, according to the name, this is a little of a hack.
http://docs.oracle.com/javase/specs/jls/se7/html/jls-15.html#jls-15.23
Thus, && computes the same result as & on boolean operands. It differs only in that the right-hand operand expression is evaluated conditionally rather than always.
http://docs.oracle.com/javase/specs/jls/se7/html/jls-15.html#jls-15.24
Thus, || computes the same result as | on boolean or Boolean operands. It differs only in that the right-hand operand expression is evaluated conditionally rather than always.
Extra: it is considered bad programming style to depend on these semantics to conditionally call code with side effects.
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if (a || b || c)
for you case,
a is true then b and c not checked.
a is false and b is true then c not checked.
a and b are false then c is checked.
the left side of the operator is evaluated first
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