Say you have these two classes, Foo and Bar where Bar extends Foo and implements Serializable
class Foo { public String name; public Foo() { this.name = "Default"; } public Foo(String name) { this.name = name; } } class Bar extends Foo implements java.io.Serializable { public int id; public Bar(String name, int id) { super(name); this.id = id; } }
Notice that Foo doesn't implement Serializable
. So what happens when bar is serialized?
public static void main(String[] args) throws Exception { FileOutputStream fStream=new FileOutputStream("objects.dat"); ObjectOutputStream oStream=new ObjectOutputStream(fStream); Bar bar=new Bar("myName",21); oStream.writeObject(bar); FileInputStream ifstream = new FileInputStream("objects.dat"); ObjectInputStream istream = new ObjectInputStream(ifstream); Bar bar1 = (Bar) istream.readObject(); System.out.println(bar1.name + " " + bar1.id); }
it prints "Default 21". The question is, why the default constructor get called when the class is not serialized?
Definition. Indicates that a class can be serialized. This class cannot be inherited.
Case 2(a): What happens when a class is serializable, but its superclass is not? Serialization: At the time of serialization, if any instance variable inherits from the non-serializable superclass, then JVM ignores the original value of that instance variable and saves the default value to the file.
In order to prevent subclass from serialization we need to implement writeObject() and readObject() methods which are executed by JVM during serialization and deserialization also NotSerializableException is made to be thrown from these methods.
Yes. Subclass need not be marked serializable explicitly.
Serializable is just a "marker interface" for a given class.
But that class must adhere to certain rules:
http://docs.oracle.com/javase/1.5.0/docs/api/java/io/Serializable.html
To allow subtypes of non-serializable classes to be serialized, the subtype may assume responsibility for saving and restoring the state of the supertype's public, protected, and (if accessible) package fields. The subtype may assume this responsibility only if the class it extends has an accessible no-arg constructor to initialize the class's state. It is an error to declare a class Serializable if this is not the case.
to answer @Sleiman Jneidi question asked in comment, in oracle documentation mentioned above, its clearly mentioned
During deserialization, the fields of non-serializable classes will be initialized using the public or protected no-arg constructor of the class. A no-arg constructor must be accessible to the subclass that is serializable. The fields of serializable subclasses will be restored from the stream.
Thus, default no-arg constructor of class Foo called of, resulted in initialization.
it may be that the defaultWriteObject can only write the non-static and non-transient fields of the current class. Once the superclass does not implements the Serializable interface, the fields in the superclass can not be serialized into the stream.
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With