I would like to make an editable table and then check the data to make sure its valid. Im not sure how to change the color of just one cell. I would like to get a cell, for example (0,0) and color the foreground to red. I have read the other posts on SO as well as Oracle about the custom ColorRenderer, but i just don't get how i would use this.
Thanks.
@Override
public Component getTableCellRendererComponent(JTable table, Object value, boolean isSelected, boolean hasFocus,
int row, int col) {
Component c = super.getTableCellRendererComponent(table, value, isSelected, hasFocus, row, col);
int control = row;
control = control % 2;
control = (control == 0) ? 1 : 0;
if (control == 1) {
c.setBackground(Color.green);
} else {
c.setBackground(Color.cyan);
}
return c;
}
I believe the correct way to do colouring in a table is via a ColorHighlighter
. The table renderers have problems to render different colours in the same column.
Here is an example of how to use highlighters. In this case it is for highlighting a cell that is not editable.
public class IsCellEditablePredicate implements HighlightPredicate {
private JXTable table;
public IsCellEditablePredicate (final JXTable table) {
this.table = table;
}
@Override
public boolean isHighlighted(Component component, ComponentAdapter componentAdapter) {
return !table.isCellEditable(componentAdapter.row,
componentAdapter.column);
}
}
and then in your code for setuping the table you add the highlighter and its colour parameters:
ColorHighlighter grayHighlighter = new ColorHighlighter(new IsCellEditablePredicate(table));
grayHighlighter.setBackground(Color.LIGHT_GRAY);
grayHighlighter.setForeground(table.getForeground());
grayHighlighter.setSelectedBackground(table.getSelectionBackground().darker());
grayHighlighter.setSelectedForeground(table.getSelectionForeground().darker());
table.setHighlighters(grayHighlighter);
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