Java int cast returns 0

Question

I have the following code:

int i = (int) 0.72;
System.out.println(i);

Which yields the following output:

0

I would of imagined that the variable i should have the value of 1 (since 0.72 > 0.5 => 1), why is this not the case?

(I imagine that when casting to int, it simply cuts of the decimal digits after the comma, not taking into account of rounding up; so I'll probably have to take care of that myself?)

Answer 1

Because when you cast a double to int, decimal part is truncated

UPDATE Math.round will give your desired output instead of Math.ceil:

 System.out.println(Math.round(0.72));
// will output 1

 System.out.println(Math.round(0.20));
// will output 0

You can use Math.ceil :

System.out.println(Math.ceil(0.72));
// will output 1
 System.out.println(Math.ceil(0.20));
// will output 1

Answer 2

Correct, casting to an int will just truncate the number. You can do something like this to get the result you are after:

int i = (int)Math.round(0.72);
System.out.println(i);

This will print 1 for 0.72 and 0 for 0.28 for example.