Java: How to initialize int array in a switch case?

Question

How can I initialize an integer array in Java like so: int[] array = {1,2,3}; inside a switch statement?

Currently, I can write:

switch(something) {
    case 0: int[] array = {1,2,3}; break;
    default: int[] array = {3,2,1};
}

But when I try to access the array variable, eclipse will complain that it might not be initialized.

If I try to declare it like int[] array; or int[] array = new int[3]; and then have the switch statement, it would say I am trying to redeclare it.

How can I resolve this issue? Final idea is to be able to initialize an array with 10 values in just one line of code, based on some logic (a switch statement).

Answer 1

Put the declaration before the switch statement. You will also need to explicitly instantiate an array of the correct type.

int[] array;
switch (something) {
    case 0: array = new int[] {1, 2, 3}; break;
    default: array = new int[] {3, 2, 1};
}

Answer 2

I would tell you to put the array declaration outside the switch block, however, you cannot use = { 1, 2, 3} syntax after the declaration. You need to initialize it the regular way, as in array = new int[] {1, 2, 3};

Answer 3

int[] array;
switch (something) {
    case 0: array = new int[]{1, 2, 3}; break;
    default: array = new int[]{3, 2, 1};
}