How would I format an int between 0
and 99
to a string which is 2 chars. E.g
4 becomes "04" 36 becomes "36"
Thanks in advance.
%d means number. %0nd means zero-padded number with a length. You build n by subtraction in your example. %s is a string. Your format string ends up being this: "%03d%s", 0, "Apple"
the %s is a 'format character', indicating "insert a string here". The extra parameters after the string in your two function calls are the values to fill into the format character placeholders: In the first example, %s will be replaced with the contents of the command variable.
%d: Specifies Decimal integer. %c: Specifies character. %T or %t: Specifies Time and date. %n: Inserts newline character.
Use String.format()
. Example:
class Test{ public static void main(String[]args){ System.out.println(String.format("%02d", 42)); //42 System.out.println(String.format("%02d", 7)); //07 } }
Edit:
luiscubal's comment got me thinking, so I figured why not benchmark the three alternatives.
import java.text.*; interface Fmt{ public String f(int x); } class Test{ static NumberFormat formatter = new DecimalFormat("00"); static Fmt f1 = new Fmt(){ public String f(int x){ return ((x<10)?"0":"") + x; } public String toString(){return "f1";} }; static Fmt f2 = new Fmt(){ public String f(int x){ return String.format("%02d", x); } public String toString(){return "f2";} }; static Fmt f3 = new Fmt(){ public String f(int x){ return formatter.format(x); } public String toString(){return "f3";} }; public static void main(String[]args){ Fmt[] fmts = new Fmt[]{f1, f2, f3, f3, f2, f1}; for (int x : new int[]{7, 42, 99}){ String s0 = null; for (Fmt fmt : fmts) if (s0==null) s0 = fmt.f(x); else if (!fmt.f(x).equals(s0)) System.exit(1); System.out.printf("%02d\n", x); for (Fmt fmt : fmts){ String s = null; int count = 0; System.gc(); long t0 = System.nanoTime(); for (int i=0; i<100000; i++){ count += fmt.f(x).length(); } long t1 = System.nanoTime(); System.out.printf(" %s:%8.2fms, count=%d\n", fmt, (t1-t0)/1000000.0, count); } } } }
The output I got was:
07 f1: 11.28ms, count=200000 f2: 195.97ms, count=200000 f3: 45.41ms, count=200000 f3: 39.67ms, count=200000 f2: 164.46ms, count=200000 f1: 6.58ms, count=200000 42 f1: 5.25ms, count=200000 f2: 163.87ms, count=200000 f3: 42.78ms, count=200000 f3: 42.45ms, count=200000 f2: 163.87ms, count=200000 f1: 5.15ms, count=200000 99 f1: 5.83ms, count=200000 f2: 168.59ms, count=200000 f3: 42.86ms, count=200000 f3: 42.96ms, count=200000 f2: 165.48ms, count=200000 f1: 5.22ms, count=200000
Turns out - if I tested correctly - that SpeedBirdNine had the most efficient solution, albeit badly presented. So I revise my solution to:
String answer = ((x<10)?"0":"") + x;
In retrospect I think it makes sense, given that my initial solution incurred the cost of parsing the format string, and I'd assume Anthony's formatter also has some manner of data structure behind it being iterated every time.
And predictably a lot faster by keeping a String[]
containing all the 100 strings, but that's probably overkill...
You can do this using NumberFormat. E.g.,
NumberFormat formatter = new DecimalFormat("00"); String s = formatter.format(4);
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