Java getting an error for implementing interface method with weaker access

Question

When I compile this code:

interface Rideable {
    String getGait();
}

public class Camel implements Rideable {
    int x = 2;

    public static void main(String[] args) {
        new Camel().go(8);
    }

    void go(int speed) {
        System.out.println((++speed * x++) 
        + this.getGait());
    }

    String getGait() {
        return " mph, lope";
    }
}

I get the following error:

Camel.java:13: error: getGait() in Camel cannot implement getGait() in Rideable
String getGait() {
       ^
  attempting to assign weaker access privileges; was public
1 error

How is the getGait method declared in the interface considered public?

Answer 1

Methods declared inside interface are implicitly public. And all variables declared in the interface are implicitly public static final (constants).

public String getGait() {
  return " mph, lope";
}