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Java getMethod with superclass parameters in method

Given:

class A
{
    public void m(List l) { ... }
}

Let's say I want to invoke method m with reflection, passing an ArrayList as the parameter to m:

List myList = new ArrayList();
A a = new A();
Method method = A.class.getMethod("m", new Class[] { myList.getClass() });
method.invoke(a, Object[] { myList });

The getMethod on line 3 will throw NoSuchMethodException because the runtime type of myList is ArrayList, not List.

Is there a good generic way around this that doesn't require knowledge of class A's parameter types?

like image 957
Jonathon Faust Avatar asked Apr 05 '10 19:04

Jonathon Faust


1 Answers

If you know the type is List, then use List.class as argument.

If you don't know the type in advance, imagine you have:

public void m(List l) {
 // all lists
}

public void m(ArrayList l) {
  // only array lists
}

Which method should the reflection invoke, if there is any automatic way?

If you want, you can use Class.getInterfaces() or Class.getSuperclass() but this is case-specific.

What you can do here is:

public void invoke(Object targetObject, Object[] parameters,
        String methodName) {
    for (Method method : targetObject.getClass().getMethods()) {
        if (!method.getName().equals(methodName)) {
            continue;
        }
        Class<?>[] parameterTypes = method.getParameterTypes();
        boolean matches = true;
        for (int i = 0; i < parameterTypes.length; i++) {
            if (!parameterTypes[i].isAssignableFrom(parameters[i]
                    .getClass())) {
                matches = false;
                break;
            }
        }
        if (matches) {
            // obtain a Class[] based on the passed arguments as Object[]
            method.invoke(targetObject, parametersClasses);
        }
    }
}
like image 125
Bozho Avatar answered Sep 23 '22 14:09

Bozho