Java get month string from integer

Question

Is there a better way to compact this method i.e. reduce the cyclomatic complexity by avoid the switch cases?

String monthString;         switch (month) {             case 1:  monthString = "January";       break;             case 2:  monthString = "February";      break;             case 3:  monthString = "March";         break;             case 4:  monthString = "April";         break;             case 5:  monthString = "May";           break;             case 6:  monthString = "June";          break;             case 7:  monthString = "July";          break;             case 8:  monthString = "August";        break;             case 9:  monthString = "September";     break;             case 10: monthString = "October";       break;             case 11: monthString = "November";      break;             case 12: monthString = "December";      break;             default: monthString = "Invalid month"; break;         }         System.out.println(monthString); 

Answer 1

Try:

import java.text.DateFormatSymbols; monthString = new DateFormatSymbols().getMonths()[month-1]; 

Alternatively, you could use SimpleDateFormat:

import java.text.SimpleDateFormat; System.out.println(new SimpleDateFormat("MMMM").format(date)); 

(You'll have to put a date with your month in a Date object to use the second option).

Answer 2

Month enum

You could use the Month enum. This enum is defined as part of the new java.time framework built into Java 8 and later.

int monthNumber = 10; Month.of(monthNumber).name(); 

The output would be:

OCTOBER

Localize

Localize to a language beyond English by calling getDisplayName on the same Enum.

String output = Month.OCTOBER.getDisplayName ( TextStyle.FULL , Locale.CANADA_FRENCH ); 

output:

octobre