Java generics type mismatch

Question

I have an abstract class defined as:

public abstract class TCV<T extends MF> {
    public Map<String, MVR<T>> operation() {
        ...
    }
}

main code:

TCV<? extends MF> o = new TCVConcrete();
Map<String, MVR< ? extends MF>> map = o.operation();

Error from eclipse:

Type mismatch: cannot convert from Map<String,MVR<capture#5-of ? extends MF>> to Map<String,MVR<? extends MF>>

EDIT

public class TCVConcrete extends TCV<MFV2> {
}

public class MFV2 extends MF {
}

Answer 1

The main problem is because you can't cast Box<Tiger> to Box<Cat>, why? You can think it as,

A Box<Cat> can contain cats and tigers, but a Box<Tiger> can contain only tigers. If you cast a Box<Tiger> to Box<Cat>, and later you throw a BlackCat into the Box<Tiger>:

Box<Cat> catBox = tigerBox;
catBox.throwHere(new BlackCat());

and then, the tigerBox is corrupted.

Let me reword your question as:

public abstract class Company<T extends Cat> {
    public Box<T> getFavBox() {
        // ...
    }
    public Set<Box<T>> getBoxes() {
        // ...
    }
}

Company<? extends Cat> o = new ETCatCompany();
Box<? extends Cat> boxes = o.getFavBox();        // ok
Set<Box<? extends Cat>> boxes = o.getBoxes();    // error

As you see, o.getFavBox() will work but o.getBoxes() not, why?

Because, you could not throw any concrete Cat into Box<? extends Cat>, which may possibly corrupt the unknown box. However, you can throw a Box<BlackCat> into Set<Box<? extends Cat>>, which may in turns corrupt a Set<Box<Tiger>>.

Or, you may think it as:

Cat ^ Tiger => Cat
Box<Cat> ^ BigBox<Cat> => Box<Cat>
Box<Cat> ^ Box<Tiger> => Box<? extends Cat>
Box<Cat> ^ BigBox<Tiger>
    => (Box<Cat> ^ BigBox<Cat>) ^ (BigBox<Cat> ^ BigBox<Tiger>)
    => Box<Cat> ^ BigBox<? extends Cat>
    => Box<? extends Cat> ^ BigBox<? extends Cat>
    => Box<? extends Cat>

Set<Box<Cat>> ^ Set<BigBox<Cat>> => Set<? extends Box<Cat>>
Set<Box<Cat>> ^ Set<Box<Tiger>> => Set<? extends Box<? extends Cat>>
Set<Box<Cat>> ^ Set<BigBox<Tiger>> => Set<? extends Box<? extends Cat>>

? extends Cat ^ ? extends Tiger => ? extends Cat
Box<? extends Cat> ^ BigBox<? extends Cat> => Box<? extends Cat>
Box<? extends Cat> ^ Box<? extends Tiger> 
    => ? extends Box<? extends (? extends Cat)>
    => ? extends Box<? extends Cat>

Set<Box<? extends Cat>> ^ Set<BigBox<? extends Cat>> 
    => Set<? extends Box<? extends Cat>>

Set<Box<? extends Cat>> ^ Set<Box<? extends Tiger>>     // You are here.
    => Set<? extends Box<? extends Cat>>

Set<Box<? extends Cat>> ^ Set<BigBox<? extends Tiger>> 
    => Set<? extends Box<? extends Cat>>

Or more likely in your case, give several operation() calls:

Map<String, MVR<?1 extends MF>> x1 = o.operation();
Map<String, MVR<?2 extends MF>> x2 = o.operation();
...
Map<String, MVR<?n extends MF>> x2 = o.operation();

Then, what's the common type of all?

x1 ^ x2 ^ ... ^ xn
    => Map<String, MVR<?1 extends MF>> ^ Map<String, MVR<?2 extends MF>> ^ ...
    => Map<String, ? extends MVR<? extends MF>> ^ ...
    ...
    => Map<String, ? extends MVR<? extends MF>>

Well, it's definitely nothing wrong with two wildcards, it's about mathematical induction...

Answer 2

The problem here is that you have two different generic definitions that could be the same:

TCV<? extends MF> o = new TCVConcrete();
    ^^^^^^^^^^^^
Map<String, MVR< ? extends MF>> map = o.operation();
                ^^^^^^^^^^^^^^

While these two could point to the same type, they could also point to two different sub-types of MF. The compiler doesn't like that.

You can solve that with a type variable in a dedicated method.
This should work:

public void <T extends MF> doSomething(){
    TCV<T> o = new TCVConcrete();
    Map<String, MVR<T>> map = o.operation();
}