I'd like to write a method that can accept a type param (or whatever the method can figure out the type from) and return a value of this type so I don't have to cast the return type.
Here is a method:
public Object doIt(Object param){ if(param instanceof String){ return "string"; }else if(param instanceof Integer){ return 1; }else{ return null; } }
When I call this method, and pass in it a String, even if I know the return type will be a String I have to cast the return Object. This is similar to the int param.
How shall I write this method to accept a type param, and return this type?
(Yes, this is legal code; see Java Generics: Generic type defined as return type only.) The return type will be inferred from the caller. However, note the @SuppressWarnings annotation: that tells you that this code isn't typesafe. You have to verify it yourself, or you could get ClassCastExceptions at runtime.
Definition: “A generic type is a generic class or interface that is parameterized over types.” Essentially, generic types allow you to write a general, generic class (or method) that works with different types, allowing for code re-use.
Any method declared void doesn't return a value. It does not need to contain a return statement, but it may do so.
Returning a Value from a Method In Java, every method is declared with a return type such as int, float, double, string, etc. These return types required a return statement at the end of the method. A return keyword is used for returning the resulted value. The void return type doesn't require any return statement.
if you don't want to have a specific interface to handle that stuff you can use a generic method in this way:
public <T> T mymethod(T type) { return type; }
Mind that in this way the compiler doesn't know anything about the type that you plan to use inside that method, so you should use a bound type, for example:
public <T extends YourType> T mymethod(T type) { // now you can use YourType methods return type; }
But you should be sure that you need a generic method, that means that the implementation of doIt
will be the same for all the types you are planning to use it with. Otherwise if every implementation is different just overload the methods, it will work fine since return type is not used for dynamic binding:
public String my(String s) { return s; } public int my(int s) { return s; } int i = my(23); String s = my("lol");
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