Java: Convert String "\uFFFF" into char

Question

Is there a standard method to convert a string like "\uFFFF" into character meaning that the string of six character contains a presentation of one unicode character?

Answer 1

char c = "\uFFFF".toCharArray()[0]; 

The value is directly interpreted as the desired string, and the whole sequence is realized as a single character.

Another way, if you are going to hard-code the value:

char c = '\uFFFF'; 

Note that \uFFFF doesn't seem to be a proper unicode character, but try with \u041f for example.

Read about unicode escapes here

Answer 2

The backslash is escaped here (so you see two of them but the s String is really only 6 characters long). If you're sure that you have exactly "\u" at the beginning of your string, simply skip them and converter the hexadecimal value:

String s = "\\u20ac";  char c = (char) Integer.parseInt( s.substring(2), 16 ); 

After that c shall contain the euro symbol as expected.